3(5y+1)-18=2(4y+3)+5

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Solution for 3(5y+1)-18=2(4y+3)+5 equation: 



3(5y+1)-18=2(4y+3)+5

We move all terms to the left:

3(5y+1)-18-(2(4y+3)+5)=0

We multiply parentheses

15y-(2(4y+3)+5)+3-18=0



We calculate terms in parentheses: -(2(4y+3)+5), so:

2(4y+3)+5

We multiply parentheses

8y+6+5

We add all the numbers together, and all the variables

8y+11

Back to the equation:

-(8y+11)



We add all the numbers together, and all the variables

15y-(8y+11)-15=0

We get rid of parentheses

15y-8y-11-15=0

We add all the numbers together, and all the variables

7y-26=0

We move all terms containing y to the left, all other terms to the right

7y=26

y=26/7

y=3+5/7

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