3(5x-4)+8=38+6(2x-5)

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Solution for 3(5x-4)+8=38+6(2x-5) equation: 



3(5x-4)+8=38+6(2x-5)

We move all terms to the left:

3(5x-4)+8-(38+6(2x-5))=0

We multiply parentheses

15x-(38+6(2x-5))-12+8=0



We calculate terms in parentheses: -(38+6(2x-5)), so:

38+6(2x-5)

determiningTheFunctionDomain
6(2x-5)+38

We multiply parentheses

12x-30+38

We add all the numbers together, and all the variables

12x+8

Back to the equation:

-(12x+8)



We add all the numbers together, and all the variables

15x-(12x+8)-4=0

We get rid of parentheses

15x-12x-8-4=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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