3(5x-4)+6=4(x+1)+6x+2

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Solution for 3(5x-4)+6=4(x+1)+6x+2 equation: 



3(5x-4)+6=4(x+1)+6x+2

We move all terms to the left:

3(5x-4)+6-(4(x+1)+6x+2)=0

We multiply parentheses

15x-(4(x+1)+6x+2)-12+6=0



We calculate terms in parentheses: -(4(x+1)+6x+2), so:

4(x+1)+6x+2

We add all the numbers together, and all the variables

6x+4(x+1)+2

We multiply parentheses

6x+4x+4+2

We add all the numbers together, and all the variables

10x+6

Back to the equation:

-(10x+6)



We add all the numbers together, and all the variables

15x-(10x+6)-6=0

We get rid of parentheses

15x-10x-6-6=0

We add all the numbers together, and all the variables

5x-12=0

We move all terms containing x to the left, all other terms to the right

5x=12

x=12/5

x=2+2/5

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