3(5x-3)+4(3+4x)=2(15x+-5)+-6

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Solution for 3(5x-3)+4(3+4x)=2(15x+-5)+-6 equation: 



3(5x-3)+4(3+4x)=2(15x+-5)+-6

We move all terms to the left:

3(5x-3)+4(3+4x)-(2(15x+-5)+-6)=0

We add all the numbers together, and all the variables

3(5x-3)+4(4x+3)-(2(15x-5)+-6)=0

We use the square of the difference formula

3(5x-3)+4(4x+3)-(2(15x-5)-6)=0

We multiply parentheses

15x+16x-(2(15x-5)-6)-9+12=0



We calculate terms in parentheses: -(2(15x-5)-6), so:

2(15x-5)-6

We multiply parentheses

30x-10-6

We add all the numbers together, and all the variables

30x-16

Back to the equation:

-(30x-16)



We add all the numbers together, and all the variables

31x-(30x-16)+3=0

We get rid of parentheses

31x-30x+16+3=0

We add all the numbers together, and all the variables

x+19=0

We move all terms containing x to the left, all other terms to the right

x=-19

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