3(5x-2)+x=10-2(1-4x)

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Solution for 3(5x-2)+x=10-2(1-4x) equation: 



3(5x-2)+x=10-2(1-4x)

We move all terms to the left:

3(5x-2)+x-(10-2(1-4x))=0

We add all the numbers together, and all the variables

3(5x-2)+x-(10-2(-4x+1))=0

We add all the numbers together, and all the variables

x+3(5x-2)-(10-2(-4x+1))=0

We multiply parentheses

x+15x-(10-2(-4x+1))-6=0



We calculate terms in parentheses: -(10-2(-4x+1)), so:

10-2(-4x+1)

determiningTheFunctionDomain
-2(-4x+1)+10

We multiply parentheses

8x-2+10

We add all the numbers together, and all the variables

8x+8

Back to the equation:

-(8x+8)



We add all the numbers together, and all the variables

16x-(8x+8)-6=0

We get rid of parentheses

16x-8x-8-6=0

We add all the numbers together, and all the variables

8x-14=0

We move all terms containing x to the left, all other terms to the right

8x=14

x=14/8

x=1+3/4

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