3(5x-1/3)=39x-7(2x+1)+6

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Solution for 3(5x-1/3)=39x-7(2x+1)+6 equation: 



3(5x-1/3)=39x-7(2x+1)+6

We move all terms to the left:

3(5x-1/3)-(39x-7(2x+1)+6)=0

We add all the numbers together, and all the variables

3(+5x-1/3)-(39x-7(2x+1)+6)=0

We multiply parentheses

15x-(39x-7(2x+1)+6)-1/3*3=0

We multiply all the terms by the denominator


15x*3*3-((39x-7(2x+1)+6))*3*3-1=0

Wy multiply elements

135x*3-((39x-7(2x+1)+6))*3*3-1=0

Wy multiply elements

405x-((39x-7(2x+1)+6))*3*3-1=0

We move all terms containing x to the left, all other terms to the right

405x-((39x-7(2x+1)+6))*3*3=1

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