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3(5x-1)(x-1)=0
We multiply parentheses ..
3(+5x^2-5x-1x+1)=0
We multiply parentheses
15x^2-15x-3x+3=0
We add all the numbers together, and all the variables
15x^2-18x+3=0
a = 15; b = -18; c = +3;
Δ = b2-4ac
Δ = -182-4·15·3
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-12}{2*15}=\frac{6}{30} =1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+12}{2*15}=\frac{30}{30} =1 $
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