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3(5x+1)=-2(2x-5)
We move all terms to the left:
3(5x+1)-(-2(2x-5))=0
We multiply parentheses
15x-(-2(2x-5))+3=0
We calculate terms in parentheses: -(-2(2x-5)), so:We get rid of parentheses
-2(2x-5)
We multiply parentheses
-4x+10
Back to the equation:
-(-4x+10)
15x+4x-10+3=0
We add all the numbers together, and all the variables
19x-7=0
We move all terms containing x to the left, all other terms to the right
19x=7
x=7/19
x=7/19
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