3(5v-2)+5v=5(v+3)

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Solution for 3(5v-2)+5v=5(v+3) equation: 



3(5v-2)+5v=5(v+3)

We move all terms to the left:

3(5v-2)+5v-(5(v+3))=0

We add all the numbers together, and all the variables

5v+3(5v-2)-(5(v+3))=0

We multiply parentheses

5v+15v-(5(v+3))-6=0



We calculate terms in parentheses: -(5(v+3)), so:

5(v+3)

We multiply parentheses

5v+15

Back to the equation:

-(5v+15)



We add all the numbers together, and all the variables

20v-(5v+15)-6=0

We get rid of parentheses

20v-5v-15-6=0

We add all the numbers together, and all the variables

15v-21=0

We move all terms containing v to the left, all other terms to the right

15v=21

v=21/15

v=1+2/5

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