3(5f+20)+(-5f)=120

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Solution for 3(5f+20)+(-5f)=120 equation:



3(5f+20)+(-5f)=120
We move all terms to the left:
3(5f+20)+(-5f)-(120)=0
We multiply parentheses
15f+(-5f)+60-120=0
We get rid of parentheses
15f-5f+60-120=0
We add all the numbers together, and all the variables
10f-60=0
We move all terms containing f to the left, all other terms to the right
10f=60
f=60/10
f=6

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