3(5c-2)-6c=3(3c-2)

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Solution for 3(5c-2)-6c=3(3c-2) equation: 



3(5c-2)-6c=3(3c-2)

We move all terms to the left:

3(5c-2)-6c-(3(3c-2))=0

We add all the numbers together, and all the variables

-6c+3(5c-2)-(3(3c-2))=0

We multiply parentheses

-6c+15c-(3(3c-2))-6=0



We calculate terms in parentheses: -(3(3c-2)), so:

3(3c-2)

We multiply parentheses

9c-6

Back to the equation:

-(9c-6)



We add all the numbers together, and all the variables

9c-(9c-6)-6=0

We get rid of parentheses

9c-9c+6-6=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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