3(5-3x)+4(3-2x)=(x+1)-3(2x+4)

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Solution for 3(5-3x)+4(3-2x)=(x+1)-3(2x+4) equation: 



3(5-3x)+4(3-2x)=(x+1)-3(2x+4)

We move all terms to the left:

3(5-3x)+4(3-2x)-((x+1)-3(2x+4))=0

We add all the numbers together, and all the variables

3(-3x+5)+4(-2x+3)-((x+1)-3(2x+4))=0

We multiply parentheses

-9x-8x-((x+1)-3(2x+4))+15+12=0



We calculate terms in parentheses: -((x+1)-3(2x+4)), so:

(x+1)-3(2x+4)

We multiply parentheses

(x+1)-6x-12

We get rid of parentheses

x-6x+1-12

We add all the numbers together, and all the variables

-5x-11

Back to the equation:

-(-5x-11)



We add all the numbers together, and all the variables

-17x-(-5x-11)+27=0

We get rid of parentheses

-17x+5x+11+27=0

We add all the numbers together, and all the variables

-12x+38=0

We move all terms containing x to the left, all other terms to the right

-12x=-38

x=-38/-12

x=3+1/6

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