3(5+2y)=4(y-2)

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Solution for 3(5+2y)=4(y-2) equation: 



3(5+2y)=4(y-2)

We move all terms to the left:

3(5+2y)-(4(y-2))=0

We add all the numbers together, and all the variables

3(2y+5)-(4(y-2))=0

We multiply parentheses

6y-(4(y-2))+15=0



We calculate terms in parentheses: -(4(y-2)), so:

4(y-2)

We multiply parentheses

4y-8

Back to the equation:

-(4y-8)



We get rid of parentheses

6y-4y+8+15=0

We add all the numbers together, and all the variables

2y+23=0

We move all terms containing y to the left, all other terms to the right

2y=-23

y=-23/2

y=-11+1/2

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