3(5*1-2)+4*1=9*1+6-2*1

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Solution for 3(5*1-2)+4*1=9*1+6-2*1 equation: 


Simplifying
3(5 * 1 + -2) + 4 * 1 = 9 * 1 + 6 + -2 * 1

Multiply 5 * 1
3(5 + -2) + 4 * 1 = 9 * 1 + 6 + -2 * 1

Combine like terms: 5 + -2 = 3
3(3) + 4 * 1 = 9 * 1 + 6 + -2 * 1

Multiply 3 * 3
9 + 4 * 1 = 9 * 1 + 6 + -2 * 1

Multiply 4 * 1
9 + 4 = 9 * 1 + 6 + -2 * 1

Combine like terms: 9 + 4 = 13
13 = 9 * 1 + 6 + -2 * 1

Multiply 9 * 1
13 = 9 + 6 + -2 * 1

Multiply -2 * 1
13 = 9 + 6 + -2

Combine like terms: 9 + 6 = 15
13 = 15 + -2

Combine like terms: 15 + -2 = 13
13 = 13

Add '-13' to each side of the equation.
13 + -13 = 13 + -13

Combine like terms: 13 + -13 = 0
0 = 13 + -13

Combine like terms: 13 + -13 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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