3(4z-1)-4(z+5)=5(z+1)

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Solution for 3(4z-1)-4(z+5)=5(z+1) equation: 



3(4z-1)-4(z+5)=5(z+1)

We move all terms to the left:

3(4z-1)-4(z+5)-(5(z+1))=0

We multiply parentheses

12z-4z-(5(z+1))-3-20=0



We calculate terms in parentheses: -(5(z+1)), so:

5(z+1)

We multiply parentheses

5z+5

Back to the equation:

-(5z+5)



We add all the numbers together, and all the variables

8z-(5z+5)-23=0

We get rid of parentheses

8z-5z-5-23=0

We add all the numbers together, and all the variables

3z-28=0

We move all terms containing z to the left, all other terms to the right

3z=28

z=28/3

z=9+1/3

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