3(4z-1)-4(z+4)=3(z+1)

Solution for 3(4z-1)-4(z+4)=3(z+1) equation:

Simplifying
3(4z + -1) + -4(z + 4) = 3(z + 1)

Reorder the terms:
3(-1 + 4z) + -4(z + 4) = 3(z + 1)
(-1 * 3 + 4z * 3) + -4(z + 4) = 3(z + 1)
(-3 + 12z) + -4(z + 4) = 3(z + 1)

Reorder the terms:
-3 + 12z + -4(4 + z) = 3(z + 1)
-3 + 12z + (4 * -4 + z * -4) = 3(z + 1)
-3 + 12z + (-16 + -4z) = 3(z + 1)

Reorder the terms:
-3 + -16 + 12z + -4z = 3(z + 1)

Combine like terms: -3 + -16 = -19
-19 + 12z + -4z = 3(z + 1)

Combine like terms: 12z + -4z = 8z
-19 + 8z = 3(z + 1)

Reorder the terms:
-19 + 8z = 3(1 + z)
-19 + 8z = (1 * 3 + z * 3)
-19 + 8z = (3 + 3z)

Solving
-19 + 8z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-19 + 8z + -3z = 3 + 3z + -3z

Combine like terms: 8z + -3z = 5z
-19 + 5z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-19 + 5z = 3 + 0
-19 + 5z = 3

Add '19' to each side of the equation.
-19 + 19 + 5z = 3 + 19

Combine like terms: -19 + 19 = 0
0 + 5z = 3 + 19
5z = 3 + 19

Combine like terms: 3 + 19 = 22
5z = 22

Divide each side by '5'.
z = 4.4

Simplifying
z = 4.4