3(4z-1)-4(z+3)=2(z+1)

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Solution for 3(4z-1)-4(z+3)=2(z+1) equation:


Simplifying
3(4z + -1) + -4(z + 3) = 2(z + 1)

Reorder the terms:
3(-1 + 4z) + -4(z + 3) = 2(z + 1)
(-1 * 3 + 4z * 3) + -4(z + 3) = 2(z + 1)
(-3 + 12z) + -4(z + 3) = 2(z + 1)

Reorder the terms:
-3 + 12z + -4(3 + z) = 2(z + 1)
-3 + 12z + (3 * -4 + z * -4) = 2(z + 1)
-3 + 12z + (-12 + -4z) = 2(z + 1)

Reorder the terms:
-3 + -12 + 12z + -4z = 2(z + 1)

Combine like terms: -3 + -12 = -15
-15 + 12z + -4z = 2(z + 1)

Combine like terms: 12z + -4z = 8z
-15 + 8z = 2(z + 1)

Reorder the terms:
-15 + 8z = 2(1 + z)
-15 + 8z = (1 * 2 + z * 2)
-15 + 8z = (2 + 2z)

Solving
-15 + 8z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-15 + 8z + -2z = 2 + 2z + -2z

Combine like terms: 8z + -2z = 6z
-15 + 6z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-15 + 6z = 2 + 0
-15 + 6z = 2

Add '15' to each side of the equation.
-15 + 15 + 6z = 2 + 15

Combine like terms: -15 + 15 = 0
0 + 6z = 2 + 15
6z = 2 + 15

Combine like terms: 2 + 15 = 17
6z = 17

Divide each side by '6'.
z = 2.833333333

Simplifying
z = 2.833333333

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