3(4z-1)-3(z+4)=4(z+1)

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Solution for 3(4z-1)-3(z+4)=4(z+1) equation:


Simplifying
3(4z + -1) + -3(z + 4) = 4(z + 1)

Reorder the terms:
3(-1 + 4z) + -3(z + 4) = 4(z + 1)
(-1 * 3 + 4z * 3) + -3(z + 4) = 4(z + 1)
(-3 + 12z) + -3(z + 4) = 4(z + 1)

Reorder the terms:
-3 + 12z + -3(4 + z) = 4(z + 1)
-3 + 12z + (4 * -3 + z * -3) = 4(z + 1)
-3 + 12z + (-12 + -3z) = 4(z + 1)

Reorder the terms:
-3 + -12 + 12z + -3z = 4(z + 1)

Combine like terms: -3 + -12 = -15
-15 + 12z + -3z = 4(z + 1)

Combine like terms: 12z + -3z = 9z
-15 + 9z = 4(z + 1)

Reorder the terms:
-15 + 9z = 4(1 + z)
-15 + 9z = (1 * 4 + z * 4)
-15 + 9z = (4 + 4z)

Solving
-15 + 9z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-15 + 9z + -4z = 4 + 4z + -4z

Combine like terms: 9z + -4z = 5z
-15 + 5z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-15 + 5z = 4 + 0
-15 + 5z = 4

Add '15' to each side of the equation.
-15 + 15 + 5z = 4 + 15

Combine like terms: -15 + 15 = 0
0 + 5z = 4 + 15
5z = 4 + 15

Combine like terms: 4 + 15 = 19
5z = 19

Divide each side by '5'.
z = 3.8

Simplifying
z = 3.8

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