3(4z-1)-3(z+1)=(z+1)

Solution for 3(4z-1)-3(z+1)=(z+1) equation:

Simplifying
3(4z + -1) + -3(z + 1) = (z + 1)

Reorder the terms:
3(-1 + 4z) + -3(z + 1) = (z + 1)
(-1 * 3 + 4z * 3) + -3(z + 1) = (z + 1)
(-3 + 12z) + -3(z + 1) = (z + 1)

Reorder the terms:
-3 + 12z + -3(1 + z) = (z + 1)
-3 + 12z + (1 * -3 + z * -3) = (z + 1)
-3 + 12z + (-3 + -3z) = (z + 1)

Reorder the terms:
-3 + -3 + 12z + -3z = (z + 1)

Combine like terms: -3 + -3 = -6
-6 + 12z + -3z = (z + 1)

Combine like terms: 12z + -3z = 9z
-6 + 9z = (z + 1)

Reorder the terms:
-6 + 9z = (1 + z)

Remove parenthesis around (1 + z)
-6 + 9z = 1 + z

Solving
-6 + 9z = 1 + z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1z' to each side of the equation.
-6 + 9z + -1z = 1 + z + -1z

Combine like terms: 9z + -1z = 8z
-6 + 8z = 1 + z + -1z

Combine like terms: z + -1z = 0
-6 + 8z = 1 + 0
-6 + 8z = 1

Add '6' to each side of the equation.
-6 + 6 + 8z = 1 + 6

Combine like terms: -6 + 6 = 0
0 + 8z = 1 + 6
8z = 1 + 6

Combine like terms: 1 + 6 = 7
8z = 7

Divide each side by '8'.
z = 0.875

Simplifying
z = 0.875