3(4z-1)-2(z+2)=(z+1)

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Solution for 3(4z-1)-2(z+2)=(z+1) equation:


Simplifying
3(4z + -1) + -2(z + 2) = (z + 1)

Reorder the terms:
3(-1 + 4z) + -2(z + 2) = (z + 1)
(-1 * 3 + 4z * 3) + -2(z + 2) = (z + 1)
(-3 + 12z) + -2(z + 2) = (z + 1)

Reorder the terms:
-3 + 12z + -2(2 + z) = (z + 1)
-3 + 12z + (2 * -2 + z * -2) = (z + 1)
-3 + 12z + (-4 + -2z) = (z + 1)

Reorder the terms:
-3 + -4 + 12z + -2z = (z + 1)

Combine like terms: -3 + -4 = -7
-7 + 12z + -2z = (z + 1)

Combine like terms: 12z + -2z = 10z
-7 + 10z = (z + 1)

Reorder the terms:
-7 + 10z = (1 + z)

Remove parenthesis around (1 + z)
-7 + 10z = 1 + z

Solving
-7 + 10z = 1 + z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1z' to each side of the equation.
-7 + 10z + -1z = 1 + z + -1z

Combine like terms: 10z + -1z = 9z
-7 + 9z = 1 + z + -1z

Combine like terms: z + -1z = 0
-7 + 9z = 1 + 0
-7 + 9z = 1

Add '7' to each side of the equation.
-7 + 7 + 9z = 1 + 7

Combine like terms: -7 + 7 = 0
0 + 9z = 1 + 7
9z = 1 + 7

Combine like terms: 1 + 7 = 8
9z = 8

Divide each side by '9'.
z = 0.8888888889

Simplifying
z = 0.8888888889

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