3(4z-1)-2(z+1)=3(z+1)

Solution for 3(4z-1)-2(z+1)=3(z+1) equation:

Simplifying
3(4z + -1) + -2(z + 1) = 3(z + 1)

Reorder the terms:
3(-1 + 4z) + -2(z + 1) = 3(z + 1)
(-1 * 3 + 4z * 3) + -2(z + 1) = 3(z + 1)
(-3 + 12z) + -2(z + 1) = 3(z + 1)

Reorder the terms:
-3 + 12z + -2(1 + z) = 3(z + 1)
-3 + 12z + (1 * -2 + z * -2) = 3(z + 1)
-3 + 12z + (-2 + -2z) = 3(z + 1)

Reorder the terms:
-3 + -2 + 12z + -2z = 3(z + 1)

Combine like terms: -3 + -2 = -5
-5 + 12z + -2z = 3(z + 1)

Combine like terms: 12z + -2z = 10z
-5 + 10z = 3(z + 1)

Reorder the terms:
-5 + 10z = 3(1 + z)
-5 + 10z = (1 * 3 + z * 3)
-5 + 10z = (3 + 3z)

Solving
-5 + 10z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-5 + 10z + -3z = 3 + 3z + -3z

Combine like terms: 10z + -3z = 7z
-5 + 7z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-5 + 7z = 3 + 0
-5 + 7z = 3

Add '5' to each side of the equation.
-5 + 5 + 7z = 3 + 5

Combine like terms: -5 + 5 = 0
0 + 7z = 3 + 5
7z = 3 + 5

Combine like terms: 3 + 5 = 8
7z = 8

Divide each side by '7'.
z = 1.142857143

Simplifying
z = 1.142857143