3(4z+1)=3(z+2)

Solution for 3(4z+1)=3(z+2) equation:

Simplifying
3(4z + 1) = 3(z + 2)

Reorder the terms:
3(1 + 4z) = 3(z + 2)
(1 * 3 + 4z * 3) = 3(z + 2)
(3 + 12z) = 3(z + 2)

Reorder the terms:
3 + 12z = 3(2 + z)
3 + 12z = (2 * 3 + z * 3)
3 + 12z = (6 + 3z)

Solving
3 + 12z = 6 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
3 + 12z + -3z = 6 + 3z + -3z

Combine like terms: 12z + -3z = 9z
3 + 9z = 6 + 3z + -3z

Combine like terms: 3z + -3z = 0
3 + 9z = 6 + 0
3 + 9z = 6

Add '-3' to each side of the equation.
3 + -3 + 9z = 6 + -3

Combine like terms: 3 + -3 = 0
0 + 9z = 6 + -3
9z = 6 + -3

Combine like terms: 6 + -3 = 3
9z = 3

Divide each side by '9'.
z = 0.3333333333

Simplifying
z = 0.3333333333