3(4y-6)+2=(2y+5)

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Solution for 3(4y-6)+2=(2y+5) equation: 



3(4y-6)+2=(2y+5)

We move all terms to the left:

3(4y-6)+2-((2y+5))=0

We multiply parentheses

12y-((2y+5))-18+2=0



We calculate terms in parentheses: -((2y+5)), so:

(2y+5)

We get rid of parentheses

2y+5

Back to the equation:

-(2y+5)



We add all the numbers together, and all the variables

12y-(2y+5)-16=0

We get rid of parentheses

12y-2y-5-16=0

We add all the numbers together, and all the variables

10y-21=0

We move all terms containing y to the left, all other terms to the right

10y=21

y=21/10

y=2+1/10

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