3(4y-12)=2(6y-18)

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Solution for 3(4y-12)=2(6y-18) equation: 



3(4y-12)=2(6y-18)

We move all terms to the left:

3(4y-12)-(2(6y-18))=0

We multiply parentheses

12y-(2(6y-18))-36=0



We calculate terms in parentheses: -(2(6y-18)), so:

2(6y-18)

We multiply parentheses

12y-36

Back to the equation:

-(12y-36)



We get rid of parentheses

12y-12y+36-36=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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