3(4y-1)-5=4(3y-2)

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Solution for 3(4y-1)-5=4(3y-2) equation:


Simplifying
3(4y + -1) + -5 = 4(3y + -2)

Reorder the terms:
3(-1 + 4y) + -5 = 4(3y + -2)
(-1 * 3 + 4y * 3) + -5 = 4(3y + -2)
(-3 + 12y) + -5 = 4(3y + -2)

Reorder the terms:
-3 + -5 + 12y = 4(3y + -2)

Combine like terms: -3 + -5 = -8
-8 + 12y = 4(3y + -2)

Reorder the terms:
-8 + 12y = 4(-2 + 3y)
-8 + 12y = (-2 * 4 + 3y * 4)
-8 + 12y = (-8 + 12y)

Add '8' to each side of the equation.
-8 + 8 + 12y = -8 + 8 + 12y

Combine like terms: -8 + 8 = 0
0 + 12y = -8 + 8 + 12y
12y = -8 + 8 + 12y

Combine like terms: -8 + 8 = 0
12y = 0 + 12y
12y = 12y

Add '-12y' to each side of the equation.
12y + -12y = 12y + -12y

Combine like terms: 12y + -12y = 0
0 = 12y + -12y

Combine like terms: 12y + -12y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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