3(4y+4)=10(2y+1)

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Solution for 3(4y+4)=10(2y+1) equation: 



3(4y+4)=10(2y+1)

We move all terms to the left:

3(4y+4)-(10(2y+1))=0

We multiply parentheses

12y-(10(2y+1))+12=0



We calculate terms in parentheses: -(10(2y+1)), so:

10(2y+1)

We multiply parentheses

20y+10

Back to the equation:

-(20y+10)



We get rid of parentheses

12y-20y-10+12=0

We add all the numbers together, and all the variables

-8y+2=0

We move all terms containing y to the left, all other terms to the right

-8y=-2

y=-2/-8

y=1/4

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