3(4y+3)=3(y+33)

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Solution for 3(4y+3)=3(y+33) equation: 



3(4y+3)=3(y+33)

We move all terms to the left:

3(4y+3)-(3(y+33))=0

We multiply parentheses

12y-(3(y+33))+9=0



We calculate terms in parentheses: -(3(y+33)), so:

3(y+33)

We multiply parentheses

3y+99

Back to the equation:

-(3y+99)



We get rid of parentheses

12y-3y-99+9=0

We add all the numbers together, and all the variables

9y-90=0

We move all terms containing y to the left, all other terms to the right

9y=90

y=90/9

y=10

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