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3(4y+10)=2(5y-1)
We move all terms to the left:
3(4y+10)-(2(5y-1))=0
We multiply parentheses
12y-(2(5y-1))+30=0
We calculate terms in parentheses: -(2(5y-1)), so:We get rid of parentheses
2(5y-1)
We multiply parentheses
10y-2
Back to the equation:
-(10y-2)
12y-10y+2+30=0
We add all the numbers together, and all the variables
2y+32=0
We move all terms containing y to the left, all other terms to the right
2y=-32
y=-32/2
y=-16
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