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3(4x-8)-6=10(x-3)+2x
We move all terms to the left:
3(4x-8)-6-(10(x-3)+2x)=0
We multiply parentheses
12x-(10(x-3)+2x)-24-6=0
We calculate terms in parentheses: -(10(x-3)+2x), so:We add all the numbers together, and all the variables
10(x-3)+2x
We add all the numbers together, and all the variables
2x+10(x-3)
We multiply parentheses
2x+10x-30
We add all the numbers together, and all the variables
12x-30
Back to the equation:
-(12x-30)
12x-(12x-30)-30=0
We get rid of parentheses
12x-12x+30-30=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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