3(4x-7)(4x+3)=0

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Solution for 3(4x-7)(4x+3)=0 equation:



3(4x-7)(4x+3)=0
We multiply parentheses ..
3(+16x^2+12x-28x-21)=0
We multiply parentheses
48x^2+36x-84x-63=0
We add all the numbers together, and all the variables
48x^2-48x-63=0
a = 48; b = -48; c = -63;
Δ = b2-4ac
Δ = -482-4·48·(-63)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-120}{2*48}=\frac{-72}{96} =-3/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+120}{2*48}=\frac{168}{96} =1+3/4 $

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