3(4x-6)+20=2(5x+3)-4x

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Solution for 3(4x-6)+20=2(5x+3)-4x equation: 



3(4x-6)+20=2(5x+3)-4x

We move all terms to the left:

3(4x-6)+20-(2(5x+3)-4x)=0

We multiply parentheses

12x-(2(5x+3)-4x)-18+20=0



We calculate terms in parentheses: -(2(5x+3)-4x), so:

2(5x+3)-4x

We add all the numbers together, and all the variables

-4x+2(5x+3)

We multiply parentheses

-4x+10x+6

We add all the numbers together, and all the variables

6x+6

Back to the equation:

-(6x+6)



We add all the numbers together, and all the variables

12x-(6x+6)+2=0

We get rid of parentheses

12x-6x-6+2=0

We add all the numbers together, and all the variables

6x-4=0

We move all terms containing x to the left, all other terms to the right

6x=4

x=4/6

x=2/3

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