3(4x-5)=3(2x-1)+12

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Solution for 3(4x-5)=3(2x-1)+12 equation: 



3(4x-5)=3(2x-1)+12

We move all terms to the left:

3(4x-5)-(3(2x-1)+12)=0

We multiply parentheses

12x-(3(2x-1)+12)-15=0



We calculate terms in parentheses: -(3(2x-1)+12), so:

3(2x-1)+12

We multiply parentheses

6x-3+12

We add all the numbers together, and all the variables

6x+9

Back to the equation:

-(6x+9)



We get rid of parentheses

12x-6x-9-15=0

We add all the numbers together, and all the variables

6x-24=0

We move all terms containing x to the left, all other terms to the right

6x=24

x=24/6

x=4

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