3(4x-5)=29-6(x-4)

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Solution for 3(4x-5)=29-6(x-4) equation: 



3(4x-5)=29-6(x-4)

We move all terms to the left:

3(4x-5)-(29-6(x-4))=0

We multiply parentheses

12x-(29-6(x-4))-15=0



We calculate terms in parentheses: -(29-6(x-4)), so:

29-6(x-4)

determiningTheFunctionDomain
-6(x-4)+29

We multiply parentheses

-6x+24+29

We add all the numbers together, and all the variables

-6x+53

Back to the equation:

-(-6x+53)



We get rid of parentheses

12x+6x-53-15=0

We add all the numbers together, and all the variables

18x-68=0

We move all terms containing x to the left, all other terms to the right

18x=68

x=68/18

x=3+7/9

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