3(4x-5)=-2x+12

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Solution for 3(4x-5)=-2x+12 equation: 



3(4x-5)=-2x+12

We move all terms to the left:

3(4x-5)-(-2x+12)=0

We multiply parentheses

12x-(-2x+12)-15=0

We get rid of parentheses

12x+2x-12-15=0

We add all the numbers together, and all the variables

14x-27=0

We move all terms containing x to the left, all other terms to the right

14x=27

x=27/14

x=1+13/14

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