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3(4x-2)=2(3x+12)
We move all terms to the left:
3(4x-2)-(2(3x+12))=0
We multiply parentheses
12x-(2(3x+12))-6=0
We calculate terms in parentheses: -(2(3x+12)), so:We get rid of parentheses
2(3x+12)
We multiply parentheses
6x+24
Back to the equation:
-(6x+24)
12x-6x-24-6=0
We add all the numbers together, and all the variables
6x-30=0
We move all terms containing x to the left, all other terms to the right
6x=30
x=30/6
x=5
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