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3(4x-12)+10=6(2x+6)
We move all terms to the left:
3(4x-12)+10-(6(2x+6))=0
We multiply parentheses
12x-(6(2x+6))-36+10=0
We calculate terms in parentheses: -(6(2x+6)), so:We add all the numbers together, and all the variables
6(2x+6)
We multiply parentheses
12x+36
Back to the equation:
-(12x+36)
12x-(12x+36)-26=0
We get rid of parentheses
12x-12x-36-26=0
We add all the numbers together, and all the variables
-62!=0
There is no solution for this equation
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