3(4x-10)+12=-7(x+3)+8

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Solution for 3(4x-10)+12=-7(x+3)+8 equation: 



3(4x-10)+12=-7(x+3)+8

We move all terms to the left:

3(4x-10)+12-(-7(x+3)+8)=0

We multiply parentheses

12x-(-7(x+3)+8)-30+12=0



We calculate terms in parentheses: -(-7(x+3)+8), so:

-7(x+3)+8

We multiply parentheses

-7x-21+8

We add all the numbers together, and all the variables

-7x-13

Back to the equation:

-(-7x-13)



We add all the numbers together, and all the variables

12x-(-7x-13)-18=0

We get rid of parentheses

12x+7x+13-18=0

We add all the numbers together, and all the variables

19x-5=0

We move all terms containing x to the left, all other terms to the right

19x=5

x=5/19

x=5/19

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