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3(4x-1)=4(5-2x)
We move all terms to the left:
3(4x-1)-(4(5-2x))=0
We add all the numbers together, and all the variables
3(4x-1)-(4(-2x+5))=0
We multiply parentheses
12x-(4(-2x+5))-3=0
We calculate terms in parentheses: -(4(-2x+5)), so:We get rid of parentheses
4(-2x+5)
We multiply parentheses
-8x+20
Back to the equation:
-(-8x+20)
12x+8x-20-3=0
We add all the numbers together, and all the variables
20x-23=0
We move all terms containing x to the left, all other terms to the right
20x=23
x=23/20
x=1+3/20
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