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3(4x+4)=16x+7-4x+5
We move all terms to the left:
3(4x+4)-(16x+7-4x+5)=0
We add all the numbers together, and all the variables
3(4x+4)-(12x+12)=0
We multiply parentheses
12x-(12x+12)+12=0
We get rid of parentheses
12x-12x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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