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3(4x+35)=5(x+21)
We move all terms to the left:
3(4x+35)-(5(x+21))=0
We multiply parentheses
12x-(5(x+21))+105=0
We calculate terms in parentheses: -(5(x+21)), so:We get rid of parentheses
5(x+21)
We multiply parentheses
5x+105
Back to the equation:
-(5x+105)
12x-5x-105+105=0
We add all the numbers together, and all the variables
7x=0
x=0/7
x=0
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