3(4x+3)=6-2(x+5)

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Solution for 3(4x+3)=6-2(x+5) equation: 



3(4x+3)=6-2(x+5)

We move all terms to the left:

3(4x+3)-(6-2(x+5))=0

We multiply parentheses

12x-(6-2(x+5))+9=0



We calculate terms in parentheses: -(6-2(x+5)), so:

6-2(x+5)

determiningTheFunctionDomain
-2(x+5)+6

We multiply parentheses

-2x-10+6

We add all the numbers together, and all the variables

-2x-4

Back to the equation:

-(-2x-4)



We get rid of parentheses

12x+2x+4+9=0

We add all the numbers together, and all the variables

14x+13=0

We move all terms containing x to the left, all other terms to the right

14x=-13

x=-13/14

x=-13/14

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