3(4x+12)=-40(x-5)

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Solution for 3(4x+12)=-40(x-5) equation: 



3(4x+12)=-40(x-5)

We move all terms to the left:

3(4x+12)-(-40(x-5))=0

We multiply parentheses

12x-(-40(x-5))+36=0



We calculate terms in parentheses: -(-40(x-5)), so:

-40(x-5)

We multiply parentheses

-40x+200

Back to the equation:

-(-40x+200)



We get rid of parentheses

12x+40x-200+36=0

We add all the numbers together, and all the variables

52x-164=0

We move all terms containing x to the left, all other terms to the right

52x=164

x=164/52

x=3+2/13

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