3(4x+1)=9(x-2)

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Solution for 3(4x+1)=9(x-2) equation: 



3(4x+1)=9(x-2)

We move all terms to the left:

3(4x+1)-(9(x-2))=0

We multiply parentheses

12x-(9(x-2))+3=0



We calculate terms in parentheses: -(9(x-2)), so:

9(x-2)

We multiply parentheses

9x-18

Back to the equation:

-(9x-18)



We get rid of parentheses

12x-9x+18+3=0

We add all the numbers together, and all the variables

3x+21=0

We move all terms containing x to the left, all other terms to the right

3x=-21

x=-21/3

x=-7

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