3(4x+1)=19+2x

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Solution for 3(4x+1)=19+2x equation:



3(4x+1)=19+2x
We move all terms to the left:
3(4x+1)-(19+2x)=0
We add all the numbers together, and all the variables
3(4x+1)-(2x+19)=0
We multiply parentheses
12x-(2x+19)+3=0
We get rid of parentheses
12x-2x-19+3=0
We add all the numbers together, and all the variables
10x-16=0
We move all terms containing x to the left, all other terms to the right
10x=16
x=16/10
x=1+3/5

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