3(4x+1)(4x-1)=72

Solution for 3(4x+1)(4x-1)=72 equation:

Simplifying
3(4x + 1)(4x + -1) = 72

Reorder the terms:
3(1 + 4x)(4x + -1) = 72

Reorder the terms:
3(1 + 4x)(-1 + 4x) = 72

Multiply (1 + 4x) * (-1 + 4x)
3(1(-1 + 4x) + 4x * (-1 + 4x)) = 72
3((-1 * 1 + 4x * 1) + 4x * (-1 + 4x)) = 72
3((-1 + 4x) + 4x * (-1 + 4x)) = 72
3(-1 + 4x + (-1 * 4x + 4x * 4x)) = 72
3(-1 + 4x + (-4x + 16x2)) = 72

Combine like terms: 4x + -4x = 0
3(-1 + 0 + 16x2) = 72
3(-1 + 16x2) = 72
(-1 * 3 + 16x2 * 3) = 72
(-3 + 48x2) = 72

Solving
-3 + 48x2 = 72

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 48x2 = 72 + 3

Combine like terms: -3 + 3 = 0
0 + 48x2 = 72 + 3
48x2 = 72 + 3

Combine like terms: 72 + 3 = 75
48x2 = 75

Divide each side by '48'.
x2 = 1.5625

Simplifying
x2 = 1.5625

Take the square root of each side:
x = {-1.25, 1.25}