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3(4v-2)=8v(2)
We move all terms to the left:
3(4v-2)-(8v(2))=0
determiningTheFunctionDomain 3(4v-2)-8v2=0
We add all the numbers together, and all the variables
-8v^2+3(4v-2)=0
We multiply parentheses
-8v^2+12v-6=0
a = -8; b = 12; c = -6;
Δ = b2-4ac
Δ = 122-4·(-8)·(-6)
Δ = -48
Delta is less than zero, so there is no solution for the equation
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