3(4u-5)=4(u+3)

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Solution for 3(4u-5)=4(u+3) equation: 



3(4u-5)=4(u+3)

We move all terms to the left:

3(4u-5)-(4(u+3))=0

We multiply parentheses

12u-(4(u+3))-15=0



We calculate terms in parentheses: -(4(u+3)), so:

4(u+3)

We multiply parentheses

4u+12

Back to the equation:

-(4u+12)



We get rid of parentheses

12u-4u-12-15=0

We add all the numbers together, and all the variables

8u-27=0

We move all terms containing u to the left, all other terms to the right

8u=27

u=27/8

u=3+3/8

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