3(4t+1)-10=t-(t+6)

Solution for 3(4t+1)-10=t-(t+6) equation:

Simplifying
3(4t + 1) + -10 = t + -1(t + 6)

Reorder the terms:
3(1 + 4t) + -10 = t + -1(t + 6)
(1 * 3 + 4t * 3) + -10 = t + -1(t + 6)
(3 + 12t) + -10 = t + -1(t + 6)

Reorder the terms:
3 + -10 + 12t = t + -1(t + 6)

Combine like terms: 3 + -10 = -7
-7 + 12t = t + -1(t + 6)

Reorder the terms:
-7 + 12t = t + -1(6 + t)
-7 + 12t = t + (6 * -1 + t * -1)
-7 + 12t = t + (-6 + -1t)

Reorder the terms:
-7 + 12t = -6 + t + -1t

Combine like terms: t + -1t = 0
-7 + 12t = -6 + 0
-7 + 12t = -6

Solving
-7 + 12t = -6

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 12t = -6 + 7

Combine like terms: -7 + 7 = 0
0 + 12t = -6 + 7
12t = -6 + 7

Combine like terms: -6 + 7 = 1
12t = 1

Divide each side by '12'.
t = 0.08333333333

Simplifying
t = 0.08333333333