3(4i+3)+4(6i+1)=43

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Solution for 3(4i+3)+4(6i+1)=43 equation: 



3(4i+3)+4(6i+1)=43

We move all terms to the left:

3(4i+3)+4(6i+1)-(43)=0

We multiply parentheses

12i+24i+9+4-43=0

We add all the numbers together, and all the variables

36i-30=0

We move all terms containing i to the left, all other terms to the right

36i=30

i=30/36

i=5/6

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