3(4d+1)+-9d=6(2+d)

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Solution for 3(4d+1)+-9d=6(2+d) equation: 



3(4d+1)+-9d=6(2+d)

We move all terms to the left:

3(4d+1)+-9d-(6(2+d))=0

We add all the numbers together, and all the variables

3(4d+1)-9d-(6(d+2))+=0

We add all the numbers together, and all the variables

-9d+3(4d+1)-(6(d+2))=0

We multiply parentheses

-9d+12d-(6(d+2))+3=0



We calculate terms in parentheses: -(6(d+2)), so:

6(d+2)

We multiply parentheses

6d+12

Back to the equation:

-(6d+12)



We add all the numbers together, and all the variables

3d-(6d+12)+3=0

We get rid of parentheses

3d-6d-12+3=0

We add all the numbers together, and all the variables

-3d-9=0

We move all terms containing d to the left, all other terms to the right

-3d=9

d=9/-3

d=-3

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